Question

For the given redox reaction:
$K_{2}C{r}_2{O}_7+14HCl\to 2KCl+2CrC{l}_3+3C{l}_2+7H_{2}O$ ,
what is the equivalent mass of $HCl$ in unit of $g/eq.$ ? Give answer to the nearest integer value after rounding off. [Given : $M_{HCl}=36.5g/mol$ ]

Answer 1

Answer: 85

$K_{2}C{r}_2{O}_7+14HCl\to 2KCl+2CrC{l}_3+3C{l}_2+7H_{2}O$
Here, the $n-$ factor of $K_{2}C{r}_2{O}_7=6$ and the $n-$ factor of $HCl=\frac{3}{7}$.
$\therefore E_{HCl}=\frac{M}{\frac{3}{7}}=\frac{7M}{3}=85.17$
$\simeq 85g/eq$