For the following reaction, the mass of water produced from 445 g of C 57 H 110 O 6 is: 2 C 57 H 110 O 6( s )+163 O 2( g ) longrightarrow 114 CO 2( g )+110 H 2 OP (1)

Question

For the following reaction, the mass of water produced from 445 g of C 57 H 110 O 6 is: 2 C 57 H 110 O 6( s )+163 O 2( g ) longrightarrow 114 CO 2( g )+110 H 2 OP (1) (A) 495 g (B) 490 g (C) 890 g (D) 445 g

Tardigrade Admin · Accepted Answer

For the following reaction, the mass of water produced from

445 g

of

C_{57} H_{110} O_{6}

is :

2 C_{57} H_{110} O_{6} (s) + 163 O_{2} (g) ⟶ 114 C O_{2} (g) + 110 H_{2} OP (1)

amoles of

C_{57} H_{110} O_{6} (s) = \frac{445}{890} = 0 \cdot 5

moles

2 C_{57} H_{110} O_{6} (s) + 163 O_{2} (g) ⟶ 114 C O_{2} (g) + 110 H_{2} O (l)

n_{H_{2} O} = \frac{110}{4} = \frac{55}{2}

m_{H_{2} O} = \frac{55}{2} \times 18

= 495 g m

Q. For the following reaction, the mass of water produced from 445g of C57​H110​O6​ is : 2C57​H110​O6​(s)+163O2​(g)⟶114CO2​(g)+110H2​OP(1)

495 g

490 g

890 g

445 g

Q. For the following reaction, the mass of water produced from $445 g$ of $C_{57} H_{110} O_{6}$ is :
$2 C_{57} H_{110} O_{6} (s) + 163 O_{2} (g) ⟶ 114 C O_{2} (g) + 110 H_{2} OP (1)$