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  4. For the following reaction, the mass of water produced from 445 g of C 57 H 110 O 6 is: 2 C 57 H 110 O 6( s )+163 O 2( g ) longrightarrow 114 CO 2( g )+110 H 2 OP (1)

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Q. For the following reaction, the mass of water produced from $445 g$ of $C _{57} H _{110} O _6$ is :
$2 C _{57} H _{110} O _6( s )+163 O _2( g ) \longrightarrow 114 CO _2( g )+110 H _2 OP (1)$

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Solution:

For the following reaction, the mass of water produced from $445 \,g$ of $C _{57} H _{110} O _6$ is :
$2 C _{57} H _{110} O _6(s)+163 O _2(g) \longrightarrow 114 CO _2(g)+110 H _2 OP (1)$
amoles of $C _{57} H _{110} O _6( s )=\frac{445}{890}=0 \cdot 5$ moles
$2 C _{57} H _{110} O _6( s )+163 O _2( g ) \longrightarrow 114 CO _2( g )+110 H _2 O ( l )$
$n_{ H _2 O }=\frac{110}{4}=\frac{55}{2}$
$m_{ H _2 O }=\frac{55}{2} \times 18$
$=495\, gm$