Question

For the following reaction scheme, percentage yields are given along the arrow:

$Xg$ and $yg$ are mass of $R$ and $U$, respectively.
(Use : Molar mass (in $gmo{l}^{-1})$ of $H,C$ and $O$ as $1,12$ and $16$, respectively)
The value of $x$ is ______.

Answer 1

Answer: 1.62

Molar mass of $P=40$
$\underset{(0.1\text{mole})}{P}\stackrel{75\%}{\to }\underset{(0.1\times \frac{3}{4})}{Q}$
$\underset{(0.1\times \frac{3}{4})}{3Q}\stackrel{40\%}{\to }\underset{(\frac{1}{3}\times 0.1\times \frac{3}{4}\times 0.4)}{R}$
So, moles of $R=0.01$ mole
Molar mass of $(R)=162$
So, $x=0.01\times 162=1.62g$