Question

For the following reaction scheme, percentage yields are given along the arrow:

$X\, g$ and $y \,g$ are mass of $R$ and $U$, respectively.
(Use : Molar mass (in $g \,mol^{-1})$ of $H, C$ and $O$ as $1, 12$ and $16$, respectively)
The value of $x$ is ______.

Answer 1

Molar mass of $P = 40$
$\underset{(0.1 \text{mole})}{ P} \xrightarrow{75\%} \underset{(0.1 \times \frac{3}{4})}{Q}$
$\underset{(0.1 \times \frac{3}{4})}{3Q} \xrightarrow{40\%} \underset{(\frac{1}{3} \times 0.1 \times \frac{3}{4} \times 0.4)}{R}$
So, moles of $R = 0.01$ mole
Molar mass of $(R) = 162$
So, $x = 0.01 \times 162 = 1.62\,g$