For the following endothermic reaction at a particular temperature, according to the equations, 2 N2O5 →4NO2+O2 2 NO2+(1/2)O2 → N2O5 the activation energies are E1 and E2 respectively, then then

Question

For the following endothermic reaction at a particular temperature, according to the equations, 2 N2O5 →4NO2+O2 2 NO2+(1/2)O2 → N2O5 the activation energies are E1 and E2 respectively, then then (A) E1> E2 (B) E1< E2 (C) E1=2E2 (D) √E1E22=1

Tardigrade Admin · Accepted Answer

Reaction one shows more activation energy and the reaction 2nd shows the less activation energy Activation energy is more for forward reaction so reaction 1 is forward reaction

Q. For the following endothermic reaction at a particular temperature, according to the equations,
$2 N_{2} O_{5} \to 4 N O_{2} + O_{2}$
$2 N O_{2} + \frac{1}{2} O_{2} \to N_{2} O_{5}$
the activation energies are $E_{1}$ and $E_{2}$ respectively, then then

$E_{1} > E_{2}$

$E_{1} < E_{2}$

$E_{1} = 2 E_{2}$

$E_{1} E_{2}^{2} = 1$

Reaction one shows more activation energy and the reaction 2nd shows the less activation energy Activation energy is more for forward reaction so reaction 1 is forward reaction

Q. For the following endothermic reaction at a particular temperature, according to the equations, 2N2​O5​→4NO2​+O2​ 2NO2​+21​O2​→N2​O5​ the activation energies are E1​ and E2​ respectively, then then

E1​>E2​

E1​<E2​

E1​=2E2​

E1​E22​​=1

Reaction one shows more activation energy and the reaction 2nd shows the less activation energy Activation energy is more for forward reaction so reaction 1 is forward reaction

Q. For the following endothermic reaction at a particular temperature, according to the equations,
$2 N_{2} O_{5} \to 4 N O_{2} + O_{2}$
$2 N O_{2} + \frac{1}{2} O_{2} \to N_{2} O_{5}$
the activation energies are $E_{1}$ and $E_{2}$ respectively, then then

$E_{1} > E_{2}$

$E_{1} < E_{2}$

$E_{1} = 2 E_{2}$

$E_{1} E_{2}^{2} = 1$