Question

For the following endothermic reaction at a particular temperature, according to the equations,
$2 N_{2}O_{5} \to4NO_{2}+O_{2}$
$2 NO_{2}+\frac{1}{2}O_{2} \to N_{2}O_{5}$
the activation energies are $E_{1}$ and $E_{2}$ respectively, then then

• A. $E_{1}>\, E_{2}$
• B. $E_{1}<\, E_{2}$
• C. $E_{1}=2E_{2}$
• D. $\sqrt{E_{1}E_{2}^{2}}=1$

Answer 1

Answer: (A)

Reaction one shows more activation energy and the reaction 2nd shows the less activation energy Activation energy is more for forward reaction so reaction 1 is forward reaction