For the circuit shown below, the zener current is

Question

For the circuit shown below, the zener current is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-zshrjuahhcr7kan4.jpg" /> (A) 5mA (B) Zero (C) 9mA (D) 18mA

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-zshrjuahhcr7al4c.jpg" /> Current through the load, IL=(40/20 × 103)=2mA Current through the battery, I=(80 - 40/2 × 103)=20mA Current through the zener diode, I2=I-IL=18mA

Q. For the circuit shown below, the zener current is

$5 m A$

Zero

$9 m A$

$18 m A$

Current through the load, $I_{L} = \frac{40}{20 \times 1 0 ^{3}} = 2 m A$
Current through the battery, $I = \frac{80 - 40}{2 \times 1 0 ^{3}} = 20 m A$
Current through the zener diode, $I_{2} = I - I_{L} = 18 m A$