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Q.
For the circuit shown below, the zener current is
NTA AbhyasNTA Abhyas 2022
Solution:
Current through the load, $I_{L}=\frac{40}{20 \times 10^{3}}=2mA$
Current through the battery, $I=\frac{80 - 40}{2 \times 10^{3}}=20mA$
Current through the zener diode, $I_{2}=I-I_{L}=18mA$