Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. For the circuit shown below, the zener current is
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
Current through the load, $I_{L}=\frac{40}{20 \times 10^{3}}=2mA$
Current through the battery, $I=\frac{80 - 40}{2 \times 10^{3}}=20mA$
Current through the zener diode, $I_{2}=I-I_{L}=18mA$