Question

For the chemical reaction
$I^{\ominus }+OC{l}^{\ominus }\to C{l}^{\ominus }+O{I}^{\ominus }$
Rate $=\frac{k\left[OC{l}^{\ominus }\right]\left[I^{\ominus }\right]}{[\stackrel{\ominus }{\mathrm{OH}}]}$
the molecularity and order with respect to $[\stackrel{\ominus }{\mathrm{OH}}]$ is

• A. 0,1
• B. 0,-1
• C. 1,0
• D. -1,0

Answer 1

Answer: (B)

a. Rate $=\frac{k\left[OC{l}^{\ominus }\right]\left[I^{\ominus }\right]}{[\stackrel{\ominus }{\mathrm{OH}}]}$
Order of reaction $=1+1-1=1$
Molecularity of reaction $=1+1=2$
b. Molecularity w.r.t. $|\stackrel{\ominus }{O}H|=0$
Order w.r.t. $\mid \stackrel{\ominus }{\mathrm{OH}}]=-1$