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AIEEEAIEEE 2009Relations and Functions - Part 2
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Solution:
Given f(x)=x3+5x+1
Now f′(x)=3x2+5>0,∀x∈R ∴f(x) is strictly increasing function ∴ It is one-one
Clearly, f(x) is a continuous function and also increasing on R, Ltx→−∞f(x)=−∞ and Ltx→∞f(x)=∞ ∴f(x) takes every value between −∞ and ∞ .
Thus, f(x) is onto function.