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Q.
For real $x,$ let $f (x) = x^3 + 5x + 1,$ then
AIEEEAIEEE 2009Relations and Functions - Part 2
Solution:
Given $f (x) = x^3 + 5x + 1$
Now $f '\left(x\right)=3x^{2}+5 > 0, ∀x ∈R$
$\therefore f \left(x\right)$ is strictly increasing function
$\therefore $ It is one-one
Clearly, $f\left(x\right)$ is a continuous function and also increasing on R,
$Lt_{x\rightarrow-\infty}\,f \left(x\right)=-\infty$ and $Lt_{x\rightarrow\infty}\,f \left(x\right)=\infty$
$\therefore f\left(x\right)$ takes every value between $−∞$ and $∞$ .
Thus, $f\left(x\right)$ is onto function.