For equilibrium, value of θ is

Question

For equilibrium, value of θ is (A) 0° (B) 30° (C) 45° (D) 60°

Tardigrade Admin · Accepted Answer

Let T be the tension in each string supporting √2 m, then T cos θ + T cos θ = √2 mg i.e. 2 T cos θ = √2 mg But T = mg also ∴ 2 mg cos θ = √2 mg i.e. cos θ = (1/√2) i.e. θ 45°

Q. For equilibrium, value of $θ$ is

$0^{\circ}$

$3 0^{\circ}$

$4 5^{\circ}$

$6 0^{\circ}$

Let T be the tension in each string supporting $2 m$ , then T cos $θ$ + T cos $θ = 2$ mg i.e. 2 T cos $θ$ = $2$ mg But T = mg also $∴$ 2 mg cos $θ = 2$ mg i.e. cos $θ = \frac{1}{2}$ i.e. $θ$ 45 $^{\circ}$

Q. For equilibrium, value of θ is

0∘

30∘

45∘

60∘