For driving a current of 3 ampere for 5 minutes in an electrical circuit, 900 joule of work is to be done. Find the emf of the source in the circuit. (in V)

Question

For driving a current of 3 ampere for 5 minutes in an electrical circuit, 900 joule of work is to be done. Find the emf of the source in the circuit. (in V) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Given I=3 ampere I =3 ampere t =5 minutes =5 × 60=300 sec. W =900 Joule W = P × t ( P = VI ) or W = VIt or V =( W / It )=(900/3 × 300)=1 volt V =1 volt

Q. For driving a current of $3$ ampere for $5$ minutes in an electrical circuit, $900$ joule of work is to be done. Find the emf of the source in the circuit. (in $V$ )

Given $I = 3$ ampere
$I = 3$ ampere
$t = 5$ minutes $= 5 \times 60 = 300 sec .$
$W = 900$ Joule
$W = P \times t (P = V I)$
or $W = V I t$
or $V = \frac{W}{I t} = \frac{900}{3 \times 300} = 1$ volt
$V = 1$ volt

Q. For driving a current of 3 ampere for 5 minutes in an electrical circuit, 900 joule of work is to be done. Find the emf of the source in the circuit. (in V)

Given I=3 ampere I=3 ampere t=5 minutes =5×60=300sec. W=900 Joule W=P×t(P=VI) or W=VIt or V=ItW​=3×300900​=1 volt V=1 volt

Q. For driving a current of $3$ ampere for $5$ minutes in an electrical circuit, $900$ joule of work is to be done. Find the emf of the source in the circuit. (in $V$ )

Given $I = 3$ ampere
$I = 3$ ampere
$t = 5$ minutes $= 5 \times 60 = 300 sec .$
$W = 900$ Joule
$W = P \times t (P = V I)$
or $W = V I t$
or $V = \frac{W}{I t} = \frac{900}{3 \times 300} = 1$ volt
$V = 1$ volt