For an AC circuit the potential difference and current are given by V=10 √2 sin ω t( in V) and I=2 √2 cos ω t (in A ) respectively. The power dissipated in the instrument is

Question

For an AC circuit the potential difference and current are given by V=10 √2 sin ω t( in V) and I=2 √2 cos ω t (in A ) respectively. The power dissipated in the instrument is (A) 20 W (B) 40 W (C) 40 √2 W (D) Zero

Tardigrade Admin · Accepted Answer

Here phase difference φ=(π/2) Sol P=V text rms I text rms cos (π/2)=0

Q. For an AC circuit the potential difference and current are given by $V = 102 sin ω t ($ in $V)$ and $I = 22 cos ω t$ (in $A$ ) respectively. The power dissipated in the instrument is

$20 W$

$40 W$

$402 W$

Zero

Here phase difference $ϕ = \frac{π}{2}$
Sol $P = V_{rms} I_{rms} cos \frac{π}{2} = 0$

Q. For an AC circuit the potential difference and current are given by V=102​sinωt( in V) and I=22​cosωt (in A ) respectively. The power dissipated in the instrument is

20W

40W

402​W