1. Tardigrade
  2. Question
  3. Physics
  4. For an AC circuit the potential difference and current are given by V=10 √2 sin ω t( in V) and I=2 √2 cos ω t (in A ) respectively. The power dissipated in the instrument is

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Q. For an AC circuit the potential difference and current are given by $V=10 \sqrt{2} \sin \omega t($ in $V)$ and $I=2 \sqrt{2} \cos \omega t$ (in $ A$ ) respectively. The power dissipated in the instrument is

Alternating Current

Solution:

Here phase difference $\phi=\frac{\pi}{2}$
Sol $P=V_{\text {rms }} I_{\text {rms }} \cos \frac{\pi}{2}=0$