For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is 1 kg, the angular frequency is ω1. When the mass block is 2 kg the angular frequency is ω2. The ratio ω2 / ω1 is

Question

For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is 1 kg, the angular frequency is ω1. When the mass block is 2 kg the angular frequency is ω2. The ratio ω2 / ω1 is (A) √2 (B) 1 / 2 (C) 2 (D) 1 / √2

Tardigrade Admin · Accepted Answer

ω=√( k / m ) (ω2/ω1)=√( m 1/ m 2)=√(1/2)

Q. For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is $1 k g$ , the angular frequency is $ω_{1}$ . When the mass block is $2 k g$ the angular frequency is $ω_{2}$ . The ratio $ω_{2} / ω_{1}$ is

$2$

$1/2$

2

$1/ 2$

$ω = \frac{k}{m}$
$\frac{ω _{2}}{ω _{1}} = \frac{m _{1}}{m _{2}} = \frac{1}{2}$

Q. For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is 1kg, the angular frequency is ω1​. When the mass block is 2kg the angular frequency is ω2​. The ratio ω2​/ω1​ is

2​

1/2

2

1/2​

ω=mk​​ ω1​ω2​​=m2​m1​​​=21​​

Q. For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is $1 k g$ , the angular frequency is $ω_{1}$ . When the mass block is $2 k g$ the angular frequency is $ω_{2}$ . The ratio $ω_{2} / ω_{1}$ is

$2$

$1/2$

$1/ 2$

$ω = \frac{k}{m}$
$\frac{ω _{2}}{ω _{1}} = \frac{m _{1}}{m _{2}} = \frac{1}{2}$