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Q. For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is $1\, kg$, the angular frequency is $\omega_1$. When the mass block is $2 \,kg$ the angular frequency is $\omega_2$. The ratio $\omega_2 / \omega_1$ isPhysics Question Image

JEE MainJEE Main 2023Oscillations

Solution:

$ \omega=\sqrt{\frac{ k }{ m }} $
$ \frac{\omega_2}{\omega_1}=\sqrt{\frac{ m _1}{ m _2}}=\sqrt{\frac{1}{2}}$