Question

For a simple harmonic motion in a mass spring system shown, the surface is frictionless. When the mass of the block is $1\, kg$, the angular frequency is $\omega_1$. When the mass block is $2 \,kg$ the angular frequency is $\omega_2$. The ratio $\omega_2 / \omega_1$ is

• A. $\sqrt{2}$
• B. $1 / 2$
• C. 2
• D. $1 / \sqrt{2}$

Answer 1

Answer: (D)

$\omega=\sqrt{\frac{ k }{ m }}$
$\frac{\omega_2}{\omega_1}=\sqrt{\frac{ m _1}{ m _2}}=\sqrt{\frac{1}{2}}$