For a second order reaction, 2A arrow Products, a plot of log t1 / 2 vs log a (where, a is initial concentration) will give an intercept equal to

Question

For a second order reaction, 2A arrow Products, a plot of log t1 / 2 vs log a (where, a is initial concentration) will give an intercept equal to (A) (1/k) (B) log ((1/2 k)) (C) log k (D) log ((1/k))

Tardigrade Admin · Accepted Answer

Kinetic equation for second order reaction is

k = \frac{1}{t} [\frac{1}{( a - x )} - \frac{1}{a}]

when

x = \frac{a}{2}

t = t_{1/2}

So

t_{1/2} = \frac{1}{k} \times \frac{1}{a}

l o g t_{1/2} = - l o g k - l o g a

Here intercept =

l o g (\frac{1}{k})

Q. For a second order reaction, $2 A \to$ Products, a plot of $lo g t_{1/2}$ vs $lo g a$ (where, $a$ is initial concentration) will give an intercept equal to

$\frac{1}{k}$

$l o g (\frac{1}{2 k})$

$l o g k$

$l o g (\frac{1}{k})$

Kinetic equation for second order reaction is
$k = \frac{1}{t} [\frac{1}{( a - x )} - \frac{1}{a}]$
when $x = \frac{a}{2}$
$t = t_{1/2}$

So $t_{1/2} = \frac{1}{k} \times \frac{1}{a}$
$l o g t_{1/2} = - l o g k - l o g a$
Here intercept = $l o g (\frac{1}{k})$

Q. For a second order reaction, 2A→ Products, a plot of logt1/2​ vs loga (where, a is initial concentration) will give an intercept equal to

k1​

log(2k1​)

logk

log(k1​)