Question

For a reaction $A+2B\to C$, the amount of $C$ formed by starting the reaction with $5$ moles of $A$ and $8$ moles of $B$ is

• A. 5 moles
• B. 8 moles
• C. 16 moles
• D. 4 moles
• E. 1 mole

Answer 1

Answer: (D)

As from rection $A+2B\to C$
It is clear that $1$ mole of $A$ reacts with $2$ moles of $B$ to form $1$ mole of $C$.
$\therefore 4$ moles of $A$ will react with $2\times 4=8$ moles of $B$ to form $4$ moles of $C$
Here, $B$ is limiting reagent.
$1$ mole of $A$ remains unreacted.