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  4. For a reaction A +2B → C, the amount of C formed by starting the reaction with 5 moles of A and 8 moles of B is

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Q. For a reaction $A +2B \to C$, the amount of $C$ formed by starting the reaction with $5$ moles of $A$ and $8$ moles of $B$ is

KEAMKEAM 2010Some Basic Concepts of Chemistry

Solution:

As from rection $A+2 B \rightarrow C$
It is clear that $1$ mole of $A$ reacts with $2$ moles of $B$ to form $1$ mole of $C$.
$\therefore 4$ moles of $A$ will react with $2 \times 4=8$ moles of $B$ to form $4$ moles of $C$
Here, $B$ is limiting reagent.
$1$ mole of $A$ remains unreacted.