For a phase change H2O(l) [][0° C . 1 bar] H2O(s)

Question

For a phase change H2O(l) <=>[][0° C . 1 bar] H2O(s) (A) Δ G = 0 (B) Δ S= 0 (C) Δ H = 0 (D) Δ U = 0

Tardigrade Admin · Accepted Answer

Δ G° = - RTIn K [Δ G° = standard free energy change, K = equilibrium constant] If a substance is in equilibrium between two phases at constant temperature and pressure, its chemical potential must have the same value in both the phases. ∴ Δ G° = 0

Q. For a phase change
$H X_{2} O X_{(l)} 0 X^{\circ} C \cdot 1 bar H X_{2} O X_{(s)}$

$Δ G = 0$

$Δ S = 0$

$Δ H = 0$

$Δ U = 0$

$Δ G^{\circ} = - RT I n K$
[ $Δ G^{\circ}$ = standard free energy change, $K$ = equilibrium constant]
If a substance is in equilibrium between two phases at constant temperature and pressure, its chemical potential must have the same value in both the phases.
$∴ Δ G^{\circ} = 0$

Q. For a phase change HX2​OX(l)​​0X∘ C⋅1 bar​HX2​OX(s)​​

ΔG=0

ΔS=0

ΔH=0

ΔU=0