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Q.
For a phase change
$\ce{ H_2O_{(l)} <=>[][0^{\circ} C . 1 \, bar] H_2O_{(s)}}$
Solution:
$\Delta G^{\circ} = - RTIn K$
[$\Delta G^{\circ}$ = standard free energy change, $K$ = equilibrium constant]
If a substance is in equilibrium between two phases at constant temperature and pressure, its chemical potential must have the same value in both the phases.
$\therefore \, \, \Delta G^{\circ} = 0$