For a particle x = A cos (ω t +(π/6)) then the value(s) of ' t ' when it is at rest is :

Question

For a particle x = A cos (ω t +(π/6)) then the value(s) of ' t ' when it is at rest is : (A) (π/6 ω) (B) (5 π/6 ω) (C) (π/3 ω) (D) (11 π/6 ω)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/d591f76f002570883104d3f21f26769f-.png" /> t1=(θ/ω)=(π-π / 6/ω)=(5 π/6 ω) t2=(2 π-π / 6/ω)=(11 π/6 ω)

Q. For a particle $x = A cos (ω t + \frac{π}{6})$ then the value(s) of ' $t$ ' when it is at rest is :

$\frac{π}{6 ω}$

$\frac{5 π}{6 ω}$

$\frac{π}{3 ω}$

$\frac{11 π}{6 ω}$

$t_{1} = \frac{θ}{ω} = \frac{π - π /6}{ω} = \frac{5 π}{6 ω}$
$t_{2} = \frac{2 π - π /6}{ω} = \frac{11 π}{6 ω}$

Q. For a particle x=Acos(ωt+6π​) then the value(s) of ' t ' when it is at rest is :

6ωπ​

6ω5π​

3ωπ​

6ω11π​