Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. For a particle $x = A \cos \left(\omega t +\frac{\pi}{6}\right)$ then the value(s) of ' $t$ ' when it is at rest is :

Oscillations

Solution:

image
$t_{1}=\frac{\theta}{\omega}=\frac{\pi-\pi / 6}{\omega}=\frac{5 \pi}{6 \omega}$
$t_{2}=\frac{2 \pi-\pi / 6}{\omega}=\frac{11 \pi}{6 \omega}$