Question

For a particle which is undergoing simple harmonic motion, the square of velocity $v^2$ is plotted against the square of displacement $x^2$. The curve will be

• A. An ellipse
• B. A straight line
• C. A circle
• D. A parabola

Answer 1

Answer: (B)

$v^2={\omega }^2{A}^2-{\omega }^2{x}^2$
$y=c-mx\to$ straight line.