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Tardigrade
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Physics
For a particle which is undergoing simple harmonic motion, the square of velocity v2 is plotted against the square of displacement x2. The curve will be
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Q. For a particle which is undergoing simple harmonic motion, the square of velocity $v^2$ is plotted against the square of displacement $x^2$. The curve will be
A
An ellipse
76%
B
A straight line
9%
C
A circle
6%
D
A parabola
10%
Solution:
$v^2 = \omega^2A^2 - \omega^2 x^2$
$y = c - mx \rightarrow$ straight line.