For a particle in SHM , if the amplitude of the displacement is a and the amplitude of velocity is v , the amplitude of acceleration is

Question

For a particle in SHM , if the amplitude of the displacement is a and the amplitude of velocity is v , the amplitude of acceleration is (A)  va  (B)  (v2/a)  (C)  (v2/2a)  (D)  (v/a)

Tardigrade Admin · Accepted Answer

Vmax =α ω and Maximum acceleration = ω2 a =((v/a))2 a=(v2/a)

Q. For a particle in $S H M$ , if the amplitude of the displacement is a and the amplitude of velocity is $v$ , the amplitude of acceleration is

$v a$

$\frac{v ^{2}}{a}$

$\frac{v ^{2}}{2 a}$

$\frac{v}{a}$

$V_{ma x} = α ω$ and
Maximum acceleration = $ω^{2} a$
$= (\frac{v}{a})^{2} a = \frac{v ^{2}}{a}$

Q. For a particle in SHM , if the amplitude of the displacement is a and the amplitude of velocity is v , the amplitude of acceleration is

va

av2​

2av2​

av​