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  4. For a particle in SHM , if the amplitude of the displacement is a and the amplitude of velocity is v , the amplitude of acceleration is

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Q. For a particle in $ SHM $ , if the amplitude of the displacement is a and the amplitude of velocity is $ v $ , the amplitude of acceleration is

MHT CETMHT CET 2010Oscillations

Solution:

$ V_{max} =\alpha \omega \, $and
Maximum acceleration = $ \omega^2 a $
$ =\bigg(\frac{v}{a}\bigg)^2 a=\frac{v^2}{a} $