For a particle executing simple harmonic motion, the amplitude is A and time period is T. The maximum speed will be

Question

For a particle executing simple harmonic motion, the amplitude is A and time period is T. The maximum speed will be (A) 4 AT (B) (2 A/T) (C) 2 π √(A/T) (D) (2 π A/T)

Tardigrade Admin · Accepted Answer

Maximum speed is given by v =A ω and ω =(2 π/T) Hence v=(2 π/T) A

Q. For a particle executing simple harmonic motion, the amplitude is $A$ and time period is $T$ . The maximum speed will be

$4 A T$

$\frac{2 A}{T}$

$2 π \frac{A}{T}$

$\frac{2 π A}{T}$

Maximum speed is given by
$v = A ω$
and $ω = \frac{2 π}{T}$
Hence $v = \frac{2 π}{T} A$

Q. For a particle executing simple harmonic motion, the amplitude is A and time period is T. The maximum speed will be

4AT

T2A​

2πTA​​

T2πA​