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Physics
For a particle executing simple harmonic motion, the amplitude is A and time period is T. The maximum speed will be
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Q. For a particle executing simple harmonic motion, the amplitude is $A$ and time period is $T$. The maximum speed will be
Oscillations
A
$4 AT$
4%
B
$\frac{2 A}{T}$
6%
C
$2 \pi \sqrt{\frac{A}{T}}$
28%
D
$\frac{2 \pi A}{T}$
62%
Solution:
Maximum speed is given by
$v =A \omega $
and $ \omega =\frac{2 \pi}{T}$
Hence $v=\frac{2 \pi}{T} A$