For a dipole, q=2 × 10-6 C and d=0.01 m. Calculate the maximum torque for this dipole if E=5 × 105 N / C.

Question

For a dipole, q=2 × 10-6 C and d=0.01 m. Calculate the maximum torque for this dipole if E=5 × 105 N / C. (A) 1 × 10-3 Nm -1 (B) 10 × 10-3 Nm -1 (C) 10 × 10-3 Nm (D) 1 × 102 Nm 2

Tardigrade Admin · Accepted Answer

τ max =p E=q(2 l) E =2 × 10-6 × 0.01 × 5 × 105 =10 × 10-3 N - m

Q. For a dipole, $q = 2 \times 1 0^{- 6} C$ and $d = 0.01 m$ . Calculate the maximum torque for this dipole if $E = 5 \times 1 0^{5} N / C$ .

$1 \times 1 0^{- 3} N m^{- 1}$

$10 \times 1 0^{- 3} N m^{- 1}$

$10 \times 1 0^{- 3} N m$

$1 \times 1 0^{2} N m^{2}$

$τ_{m a x} = pE = q (2 l) E$
$= 2 \times 1 0^{- 6} \times 0.01 \times 5 \times 1 0^{5}$
$= 10 \times 1 0^{- 3} N - m$

Q. For a dipole, q=2×10−6C and d=0.01m. Calculate the maximum torque for this dipole if E=5×105N/C.

1×10−3Nm−1

10×10−3Nm−1

10×10−3Nm

1×102Nm2