Question

For a dipole, $q=2 \times 10^{-6} C$ and $d=0.01\, m$. Calculate the maximum torque for this dipole if $E=5 \times 10^{5} N / C$.

• A. $1 \times 10^{-3} Nm ^{-1}$
• B. $10 \times 10^{-3} Nm ^{-1}$
• C. $10 \times 10^{-3} Nm$
• D. $1 \times 10^{2} Nm ^{2}$

Answer 1

Answer: (C)

$\tau_{\max }=p E=q(2 l) E$
$=2 \times 10^{-6} \times 0.01 \times 5 \times 10^{5}$
$=10 \times 10^{-3} N - m$