For a current carrying inductor, emf associated is 20 mV. Now, current through it changes from 6 A to 2 A in 2 s. The coefficient of mutual inductance is

Question

For a current carrying inductor, emf associated is 20 mV. Now, current through it changes from 6 A to 2 A in 2 s. The coefficient of mutual inductance is (A) 20 mH (B) 10 mH (C) 1 mH (D) 2 mH

Tardigrade Admin · Accepted Answer

|e| = L (dI/dt) Here, e = 20 m V = 20 ×10-3 V (dI/dt) = (6-2/2) = 2 (A/s ) L = ? ⇒ 20 ×10-3 = L × 2 ∴ L= 10 ×10-3 H = 10 mH

Q. For a current carrying inductor, emf associated is $20 mV$ . Now, current through it changes from $6 A$ to $2 A$ in $2 s$ . The coefficient of mutual inductance is

20 mH

10 mH

1 mH

2 mH

$∣ e ∣ = L \frac{d I}{d t}$
Here, $e = 20 m$
$V = 20 \times 1 0^{- 3} V$
$\frac{d I}{d t} = \frac{6 - 2}{2} = 2 \frac{A}{s}$
$L = ?$
$\Rightarrow 20 \times 1 0^{- 3} = L \times 2$
$∴ L = 10 \times 1 0^{- 3} H = 10 m H$

Q. For a current carrying inductor, emf associated is 20mV. Now, current through it changes from 6A to 2A in 2s. The coefficient of mutual inductance is