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  4. For a current carrying inductor, emf associated is 20 mV. Now, current through it changes from 6 A to 2 A in 2 s. The coefficient of mutual inductance is

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Q. For a current carrying inductor, emf associated is $20\,mV$. Now, current through it changes from $6\,A $ to $2\,A$ in $2\,s$. The coefficient of mutual inductance is

VITEEEVITEEE 2016

Solution:

$\left|e\right| = L \frac{dI}{dt} $
Here, $e = 20 \,m$
$V = 20 \times10^{-3} V$
$ \frac{dI}{dt} = \frac{6-2}{2} = 2 \frac{A}{s }$
$ L = ? $
$\Rightarrow 20 \times10^{-3} = L \times 2$
$ \therefore L= 10 \times10^{-3} H = 10 \, mH$