For a chemical reaction A→B, it is found that the rate of reaction doubles when the concentration of A is increased four times. The order in A for this reaction is

Question

For a chemical reaction A→B, it is found that the rate of reaction doubles when the concentration of A is increased four times. The order in A for this reaction is (A) Two (B) One (C) Half (D) Zero

Tardigrade Admin · Accepted Answer

Let Rate = k[A]n r1 = k an r2 = k(4a)n but r2/r1=2 =n=1/2 = Order of reaction = 1/2

Q. For a chemical reaction A $\to$ B, it is found that the rate of reaction doubles when the concentration of A is increased four times. The order in A for this reaction is

Two

One

Half

Zero

Let Rate $= k [A]^{n}$
$r_{1} = k a^{n}$
$r_{2} = k (4 a)^{n} b u t r_{2} / r_{1} = 2$
$= n = 1/2$
= Order of reaction = 1/2

Q. For a chemical reaction A→B, it is found that the rate of reaction doubles when the concentration of A is increased four times. The order in A for this reaction is

Two

One

Half

Zero

Let Rate =k[A]n r1​=kan r2​=k(4a)nbutr2​/r1​=2 =n=1/2 = Order of reaction = 1/2

Q. For a chemical reaction A $\to$ B, it is found that the rate of reaction doubles when the concentration of A is increased four times. The order in A for this reaction is

Let Rate $= k [A]^{n}$
$r_{1} = k a^{n}$
$r_{2} = k (4 a)^{n} b u t r_{2} / r_{1} = 2$
$= n = 1/2$
= Order of reaction = 1/2