For a chemical reaction 2X + Y →Z the rate of appearance of Z is 0.05 mol L-1 per min. The rate of disappearance of X will be

Question

For a chemical reaction 2X + Y →Z the rate of appearance of Z is 0.05 mol L-1 per min. The rate of disappearance of X will be (A) 0.05 mol L-1 per hour (B) 0.05 mol L-1 per min (C) 0.1 mol L-1 min-1 (D) 0.2 mol L-1 per min

Tardigrade Admin · Accepted Answer

Rate of disappearance of X -2 × rate of appearance of Z = 2 × 0.5 =0.1 mol L-1

Q. For a chemical reaction 2X + Y $\to$ Z the rate of appearance of Z is 0.05 mol $L^{- 1}$ per min. The rate of disappearance of X will be

$0.05 m o l L^{- 1}$ per hour

$0.05 m o l L^{- 1}$ per min

$0.1 m o l L^{- 1} mi n^{- 1}$

$0.2 m o l L^{- 1} p er min$

Rate of disappearance of X -2 $\times$ rate of appearance of Z $= 2 \times 0.5 = 0.1 m o l L^{- 1}$

Q. For a chemical reaction 2X + Y →Z the rate of appearance of Z is 0.05 mol L−1 per min. The rate of disappearance of X will be

0.05molL−1 per hour

0.05molL−1 per min

0.1molL−1min−1

0.2molL−1permin