Tardigrade
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Tardigrade
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Chemistry
For a chemical reaction 2X + Y →Z the rate of appearance of Z is 0.05 mol L-1 per min. The rate of disappearance of X will be
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Q. For a chemical reaction 2X + Y $\to$Z the rate of appearance of Z is 0.05 mol $L^{-1}$ per min. The rate of disappearance of X will be
Chemical Kinetics
A
$0.05\, mol\, L^{-1}$ per hour
8%
B
$0.05\, mol\, L^{-1}$ per min
20%
C
$0.1\, mol\, L^{-1}\, min^{-1}$
61%
D
$0.2\, mol\, L^{-1}\, per\, min$
10%
Solution:
Rate of disappearance of X -2 $\times $ rate of appearance of Z $= 2 \times 0.5 =0.1\,mol\, L^{-1}$