For a cell, a graph is plotted between the potential difference V across the terminals of the cell and the current I drawn from the cell (see figure). The emf and the internal resistance of the cell are E and r , respectively Then

Question

For a cell, a graph is plotted between the potential difference V across the terminals of the cell and the current I drawn from the cell (see figure). The emf and the internal resistance of the cell are E and r , respectively Then <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/8a30febd1d1c8d21acfc03ef61c70a68-.png" /> (A) E =2V, r=0.5 Ω (B) E =2 V, r=0.4 Ω (C) E > 2 V, r = 0.5 Ω (D) E > 2 V, r=0.4 Ω

Tardigrade Admin · Accepted Answer

V =E -ir When i=0, the potential reading is 2 V. Hence emf is 2 V When V=0, i =5 A This gives r =0.4 Ω

Q. For a cell, a graph is plotted between the potential difference $V$ across the terminals of the cell and the current $I$ drawn from the cell (see figure). The emf and the internal resistance of the cell are $E$ and $r$ , respectively Then

$E = 2 V, r = 0.5 Ω$

$E = 2 V, r = 0.4 Ω$

$E > 2 V, r = 0.5 Ω$

$E > 2 V, r = 0.4 Ω$

$V = E - i r$ When $i = 0$ , the potential reading is 2 V. Hence emf is $2 V$ When $V = 0, i = 5 A$ This gives $r = 0.4 Ω$

Q. For a cell, a graph is plotted between the potential difference V across the terminals of the cell and the current I drawn from the cell (see figure). The emf and the internal resistance of the cell are E and r , respectively Then

E=2V,r=0.5Ω

E=2V,r=0.4Ω

E>2V,r=0.5Ω

E>2V,r=0.4Ω