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Q. For a cell, a graph is plotted between the potential difference $V$ across the terminals of the cell and the current $I$ drawn from the cell (see figure). The emf and the internal resistance of the cell are $E$ and $r$ , respectively Then
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Current Electricity

Solution:

$V =E -ir$ When $i=0$, the potential reading is 2 V. Hence emf is $2\,V$ When $V=0, i =5\,A$ This gives $r =0.4 \,\Omega$