For 14 g of CO the wrong statement is :

Question

For 14 g of CO the wrong statement is : (A) it occupies 2.24 litres at NTP (B) it corresponds to (1/2) mole of CO (C) it corresponds to same mole of CO and nitrogen gas (D) it corresponds to 3.01× 1023 molecules of CO

Tardigrade Admin · Accepted Answer

We know that 14 gm CO =(14/28)=0.5 mol Therefore, it corresponds to (1/2) mole of CO and nitrogen gas. 0.5 mol is equivalent to 3.01 × 1023 molecules.

Q. For $14 g$ of $CO$ the wrong statement is :

it occupies 2.24 litres at NTP

it corresponds to $\frac{1}{2}$ mole of CO

it corresponds to same mole of CO and nitrogen gas

it corresponds to $3.01 \times 1 0^{23}$ molecules of CO

We know that $14 g m CO = \frac{14}{28} = 0.5 m o l$ Therefore, it corresponds to $\frac{1}{2}$ mole of CO and nitrogen gas. $0.5$ mol is equivalent to $3.01 \times 1 0^{23}$ molecules.

Q. For 14g of CO the wrong statement is :

it occupies 2.24 litres at NTP

it corresponds to 21​ mole of CO

it corresponds to same mole of CO and nitrogen gas

it corresponds to 3.01×1023 molecules of CO

We know that 14gmCO=2814​=0.5mol Therefore, it corresponds to 21​ mole of CO and nitrogen gas. 0.5 mol is equivalent to 3.01×1023 molecules.

Q. For $14 g$ of $CO$ the wrong statement is :

it corresponds to $\frac{1}{2}$ mole of CO

it corresponds to $3.01 \times 1 0^{23}$ molecules of CO

We know that $14 g m CO = \frac{14}{28} = 0.5 m o l$ Therefore, it corresponds to $\frac{1}{2}$ mole of CO and nitrogen gas. $0.5$ mol is equivalent to $3.01 \times 1 0^{23}$ molecules.