Question

For $14\, g$ of $CO$ the wrong statement is :

• A. it occupies 2.24 litres at NTP
• B. it corresponds to $ \frac{1}{2} $ mole of CO
• C. it corresponds to same mole of CO and nitrogen gas
• D. it corresponds to $ 3.01\times 10^{23}$ molecules of CO

Answer 1

Answer: (A)

We know that $14\, gm CO =\frac{14}{28}=0.5\, mol$ Therefore, it corresponds to $\frac{1}{2}$ mole of CO and nitrogen gas. $0.5$ mol is equivalent to $3.01 \times 10^{23}$ molecules.