For 1 mol of an ideal gas at a constant temperature T, the plot of (log P) against (log V) is a (P: Pressure, V: Volume)

Question

For 1 mol of an ideal gas at a constant temperature T, the plot of (log P) against (log V) is a (P: Pressure, V: Volume) (A) Straight line parallel to x-axis (B) Straight line with a negative slope (C) Curve starting at origin (D) Straight line passing through origin

Tardigrade Admin · Accepted Answer

According to Boyle's law, PV = constant ∴ log P + log V = constant log P = - log V + constant Hence, the plot of log P vs log V is straight line with negative slope.

Q. For 1 mol of an ideal gas at a constant temperature $T$ , the plot of $(l o g P)$ against $(l o g V)$ is a ( $P$ : Pressure, $V$ : Volume)

Straight line parallel to x-axis

Straight line with a negative slope

Curve starting at origin

Straight line passing through origin

According to Boyle's law, $P V =$ constant
$∴ l o g P + l o g V =$ constant
$l o g P = - l o g V +$ constant
Hence, the plot of log $P$ vs log $V$ is straight line with negative slope.

Q. For 1 mol of an ideal gas at a constant temperature T, the plot of (logP) against (logV) is a (P: Pressure, V: Volume)