Q. For 1 mol of an ideal gas at a constant temperature $T$, the plot of $(log\, P)$ against $(log\, V)$ is a ($P$: Pressure, $V$: Volume)
AIEEEAIEEE 2012States of Matter
Solution:
According to Boyle's law, $PV =$ constant
$\therefore log \,P + log \,V =$ constant
$log\, P = - log\, V +$ constant
Hence, the plot of log $P$ vs log $V$ is straight line with negative slope.
