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Tardigrade
Question
Mathematics
For 0< x< (π/2), ∫ limits1 / 2√3 / 2 ln (e cos x) ⋅ d( sin x) is equal to :
Q. For
0
<
x
<
2
π
,
1/2
∫
3
/2
ln
(
e
c
o
s
x
)
⋅
d
(
sin
x
)
is equal to :
104
102
Integrals
Report Error
A
12
π
B
6
π
C
4
1
[(
3
−
1
)
+
(
sin
3
−
sin
1
)]
D
4
1
[(
3
−
1
)
−
(
sin
3
−
sin
1
)]
Solution:
I
=
π
/6
∫
π
/3
cos
x
cos
x
d
x
=
π
/6
∫
π
/3
cos
2
x
d
x
=
π
/6
∫
π
/3
sin
2
x
d
x
⇒
2
I
=
π
/6
∫
π
/3
d
x
=
6
π
⇒
I
=
12
π