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Tardigrade
Question
Chemistry
Following two half cells form a complete cell which has Δ G °( in kJ ) value 2 H ++1 / 2 O 2+2 e - arrow H 2 O ; E °=+1.23 V Fe 2++2 e - arrow Fe ( s ) E°=-0.44 V
Q. Following two half cells form a complete cell which has
Δ
G
∘
(
in
k
J
)
value
2
H
+
+
1/2
O
2
+
2
e
−
→
H
2
O
;
E
∘
=
+
1.23
V
F
e
2
+
+
2
e
−
→
F
e
(
s
)
E
∘
=
−
0.44
V
2867
197
Electrochemistry
Report Error
A
-122 kJ
13%
B
-222 kJ
10%
C
-322 kJ
72%
D
-422 kJ
4%
Solution:
Δ
G
0
=
−
n
F
E
0
=
−
2
×
96500
×
[
1.23
−
(
−
0.44
)]
J
=
−
322310
J
=
−
322.31
k
J