Q.
Following two half cells form a complete cell which has $\Delta G ^{\circ}($ in $kJ )$ value
$2 H ^{+}+1 / 2 O _{2}+2 e ^{-} \rightarrow H _{2} O ; \quad E ^{\circ}=+1.23 V$
$Fe ^{2+}+2 e ^{-} \rightarrow Fe ( s )$
$E^{\circ}=-0.44 V$
Electrochemistry
Solution: