Following is the substitution reaction in which -CN replaces -Cl R - Cl + underset text(alcoholic)KCN xrightarrow[Δ] R - CN + KCl To obtain propanenitrile, R-Cl should be

Question

Following is the substitution reaction in which -CN replaces -Cl R - Cl + underset text(alcoholic)KCN xrightarrow[Δ] R - CN + KCl To obtain propanenitrile, R-Cl should be (A) chloroethane (B) 1-chloropropane (C) chloromethane (D) 2-chloropropane

Tardigrade Admin · Accepted Answer

C 2 H 5- Cl + underset(alc)KCN xrightarrowΔ C 2 H 5- CN + KCl Hence, to obtain propanenitrile, R- Cl should be chloroethane.

Q. Following is the substitution reaction in which $- CN$ replaces $- Cl$
$R - Cl + (alcoholic) K CN Δ R - CN + K Cl$
To obtain propanenitrile, $R - Cl$ should be

chloroethane

$1$ -chloropropane

chloromethane

$2$ -chloropropane

$C_{2} H_{5} - Cl + (a l c) K CN Δ C_{2} H_{5} - CN + K Cl$

Hence, to obtain propanenitrile, $R - Cl$ should be chloroethane.

Q. Following is the substitution reaction in which −CN replaces −Cl R−Cl+(alcoholic)KCN​Δ​R−CN+KCl To obtain propanenitrile, R−Cl should be

chloroethane

1-chloropropane

chloromethane

2-chloropropane

C2​H5​−Cl+(alc)KCN​Δ​C2​H5​−CN+KCl Hence, to obtain propanenitrile, R−Cl should be chloroethane.

Q. Following is the substitution reaction in which $- CN$ replaces $- Cl$
$R - Cl + (alcoholic) K CN Δ R - CN + K Cl$
To obtain propanenitrile, $R - Cl$ should be

$1$ -chloropropane

$2$ -chloropropane

$C_{2} H_{5} - Cl + (a l c) K CN Δ C_{2} H_{5} - CN + K Cl$

Hence, to obtain propanenitrile, $R - Cl$ should be chloroethane.