Fluorine is more electronegative than either boron or phosphorus. What conclusion can be drawn from the fact that BF 3 has no dipole moment but PF 3 does?

Question

Fluorine is more electronegative than either boron or phosphorus. What conclusion can be drawn from the fact that BF 3 has no dipole moment but PF 3 does? (A) BF 3 is not spherically symmetrical, but PF 3 is (B) BF 3 molecule must be linear (C) The atomic radius of P is larger than the atomic radius of B (D) The BF 3 molecule must be planar triangular

Tardigrade Admin · Accepted Answer

In BF3, B is s p2 hybridised and compound is planar triangular so that BF 3 is non-polar.

Q. Fluorine is more electronegative than either boron or phosphorus. What conclusion can be drawn from the fact that $B F_{3}$ has no dipole moment but $P F_{3}$ does?

$B F_{3}$ is not spherically symmetrical, but $P F_{3}$ is

$B F_{3}$ molecule must be linear

The atomic radius of $P$ is larger than the atomic radius of $B$

The $B F_{3}$ molecule must be planar triangular

In $B F_{3}, B$ is $s p^{2}$ hybridised and compound is planar triangular so that $B F_{3}$ is non-polar.

Q. Fluorine is more electronegative than either boron or phosphorus. What conclusion can be drawn from the fact that BF3​ has no dipole moment but PF3​ does?

BF3​ is not spherically symmetrical, but PF3​ is

BF3​ molecule must be linear

The atomic radius of P is larger than the atomic radius of B

The BF3​ molecule must be planar triangular