Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Fluorine is more electronegative than either boron or phosphorus. What conclusion can be drawn from the fact that $BF _{3}$ has no dipole moment but $PF _{3}$ does?

The p-Block Elements

Solution:

In $BF_{3}, B$ is $s p^{2}$ hybridised and compound is planar triangular so that $BF _{3}$ is non-polar.