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Q.
Fluorine is more electronegative than either boron or phosphorus. What conclusion can be drawn from the fact that $BF _{3}$ has no dipole moment but $PF _{3}$ does?
The p-Block Elements
Solution:
In $BF_{3}, B$ is $s p^{2}$ hybridised and compound is planar triangular so that $BF _{3}$ is non-polar.